\[ V = \frac{1}{3}\pi r^2 h \]
![\[ V = \frac{1}{3}\pi r^2 h \]](https://soloferat.biz.id/images/v--frac13pi-r2-h-.jpg)
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- Where \( P = 5,000 \), \( r = 0.06 \), \( t = 4 \):
- \[ I = 5,000 \times 0.06 \times 4 = 1,200 \]
- A cone has a radius of 3 cm and a height of 4 cm. What is its volume? (Use \( \pi \approx 3.14 \))
- Substitute \( r = 3 \), \( h = 4 \):
- \[ V = \frac{1}{3} \times 3.14 \times 3^2 \times 4 \]
- \[ V = \frac{1}{3} \times 3.14 \times 9 \times 4 \]
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