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\[ t = \frac{20}{9.8} \approx 2.04 \, \text{seconds} \]A sphere has a volume of 288π cubic centimeters. What is the radius of the sphere? (Use \( V = \frac{4}{3}\pi r^3 \))Given volume \( V = 288\pi \), solve for \( r \):\[ \frac{4}{3}\pi r^3 = 288\pi \]\[ \frac{4}{3}r^3 = 288 \]\[ r^3 = 288 \times \frac{3}{4} = 216 \]\[ r = \sqrt[3]{216} = 6 \, \text{cm} \]Substituting \( l = 4 \), \( w = 5 \), \( h = 6 \):\[ SA = 2(4 \times 5 + 4 \times 6 + 5 \times 6) \]\[ SA = 2 \times 74 = 148 \, \text{square centimeters} \]