\( \log_2(x) + \log_2(x-3) = 3 \) を \( x \) について解きます。
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- \( v = 50 \) m/s、\( \theta = 30^\circ \) 、\( \sin(60^\circ) = \frac{\sqrt{3}}{2} \) です。
- \( R = \frac{50^2 \times \frac{\sqrt{3}}{2}}{9.8} = \frac{2500 \times \frac{\sqrt{3}}{2}}{9.8} \approx 220.86 \) メートルです。
- #### 220.86
- 対数を組み合わせます：\( \log_2(x(x-3)) = 3 \)。
- 指数形式に変換します：\( x(x-3) = 2^3 = 8 \)。
- 因数分解：\( (x-4)(x+2) = 0 \)，したがって \( x = 4 \) または \( x = -2 \) です。
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